# 3

3fdsfdsfds

#### stapel

##### Super Moderator
Staff member
If x = 12, then plugging "12" in for "x" in the original equation should work. Let's see:

. . . . .3([12] - 5) ?=? [12] + 9

. . . . .3(7) ?=? 21

. . . . .21 ?=? 21

This certainly looks like a valid solution to me. Checking over your work, all your steps look perfectly correct.

I have no idea what your instructor might be getting at, but, if the problem is as posted, you're right.

Eliz.

#### Dashival

##### New member
Thanks for clarifying, I'll print out your response and show it to him.

#### Denis

##### Senior Member
The equation you posted is:
3(x-5) = (x+9)
and x = 12 is correct as Eliz told you.

Are you sure you're using same equation as your teacher?
The right side make me suspicious: why the brackets?
Looks like that could be 2(x+9)...or something(x+9).

#### Dark Knight 496

##### New member
Some teachers just won't admit their mistakes... maybe that's what is causing the problem

#### stapel

##### Super Moderator
Staff member
Dark Knight 496 said:
Some teachers just won't admit their mistakes.