G
Guest
Guest
Hi.
I'm stuck on on the last part of this problem. Any help would
be greatly appreciated....I have answered parts 1 through
3, i believe correctly, now i just need help with 4 and 5.
thanks in advance.
Suppose you wanted to construct a fence around a garden plot in the form of a rectangle. On the neighbor’s side it’s going to need heavy-duty fencing that costs $2.00 per foot. The other three sides can be made of standard fencing material that costs $1.20 foot. You have $200 to spend.
Question 1 (10 points)
How many different rectangles would it be possible to enclose for $200?
It would be possible to enclose an infinite amount of rectangles as there are no size limitations set forth in the initial problem.
Save answer
Question 2 (20 points)
Write an equation using two variables for the total cost of the fence. Use x and y to represent the width and length of the rectangle. Solve the equation for one of the variables (either x or y).
2y + 1.2x + 1.2x + 1.2y = 200
2.4x + 3.2y = 200
3.2y = 200 - 2.4x
y = 200- 2.4x / 3.2
y = 50 - .6x / .8
y = 25 - .3x/.4
y = 250 - 3x/4
Save answer
Question 3 (20 points)
Given that Area = (x)(y), now write the area function for this problem using ONLY ONE VARIABLE (by making a substitution using the equation from #2).
Area = (x)(250-3x)/4
y = 250x - 3x^2 / 4
Save answer
Question 4 (40 points)
What dimensions will give the maximum area inside the fence?
???
Save answer
Question 5 (10 points)
What will be the maximum area?
???
[/b]
I'm stuck on on the last part of this problem. Any help would
be greatly appreciated....I have answered parts 1 through
3, i believe correctly, now i just need help with 4 and 5.
thanks in advance.
Suppose you wanted to construct a fence around a garden plot in the form of a rectangle. On the neighbor’s side it’s going to need heavy-duty fencing that costs $2.00 per foot. The other three sides can be made of standard fencing material that costs $1.20 foot. You have $200 to spend.
Question 1 (10 points)
How many different rectangles would it be possible to enclose for $200?
It would be possible to enclose an infinite amount of rectangles as there are no size limitations set forth in the initial problem.
Save answer
Question 2 (20 points)
Write an equation using two variables for the total cost of the fence. Use x and y to represent the width and length of the rectangle. Solve the equation for one of the variables (either x or y).
2y + 1.2x + 1.2x + 1.2y = 200
2.4x + 3.2y = 200
3.2y = 200 - 2.4x
y = 200- 2.4x / 3.2
y = 50 - .6x / .8
y = 25 - .3x/.4
y = 250 - 3x/4
Save answer
Question 3 (20 points)
Given that Area = (x)(y), now write the area function for this problem using ONLY ONE VARIABLE (by making a substitution using the equation from #2).
Area = (x)(250-3x)/4
y = 250x - 3x^2 / 4
Save answer
Question 4 (40 points)
What dimensions will give the maximum area inside the fence?
???
Save answer
Question 5 (10 points)
What will be the maximum area?
???
[/b]