polynomials

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Confusing me is the polynomials. My question as an example...anyone got any baby steps for me???

(2c to the third power dto the second power)to the fifth power x ( c to the sixth power d to the either power) to the third power divided by ( 4 c to the second power d)

This was hard to type because of the power position so I wrote it out.
Anyone understand me? :cry:
 
Hello, afreemanny!

Did you mean "eighth", not "either"?

(2c to the third power, d to the second power)to the fifth power
times( c to the sixth power, d to the eighth power) to the third power,
divided by ( 4 c to the second power, d)
Click to expand...
You can use ^ to indicate an exponent.

(2c^3 d^2)^5 (c^6 d^8)^3 / (4c^2 d)

I assume you know the basic rules for exponents . . .

. . . . . . . . . (2c<sup>3</sup>d<sup>2</sup>)<sup>5</sup> (c<sup>6</sup>d<sup>8</sup>)<sup>3</sup> . . . .(2<sup>5</sup>)(c<sup>3</sup>)<sup>5</sup>(d<sup>2</sup>)<sup>5</sup> (c<sup>6</sup>)<sup>3</sup>(d<sup>8</sup>)<sup>3</sup>
We have: . -------------------- . = . -------------------------------
. . . . . . . . . . . . .4c<sup>2</sup>d . . . . . . . . . . . . . . . . 4c<sup>2</sup>d

. . . . . . 32 c<sup>15</sup> d<sup>10</sup> c<sup>18</sup> d<sup>24</sup> . . . . 32 c<sup>33</sup> d<sup>34</sup>
. . . = . ------------------------ . = . -------------- . = . 8 c<sup>31</sup> d<sup>33</sup>
. . . . . . . . . . . . 4c<sup>2</sup>d . . . . . . . . . . . 4c<sup>2</sup>d
 
thanks

I do know the basic rules for exponents but I got comfused about this one.
I thank you for all your help. You are great! I wish I knew you. :D
 
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