exponential and logarithimic functions

[Elaine]

express logbs/t as a difference of logarithms


Is this solution logbt-logbs?


Also....

convert logn T=-x to an expoenetial equation

Is this n-x=T???


Thank you in advance for your help[/i]

 

[stapel]

express logbs/t as a difference of logarithms Is this solution logbt-logbs?

If you mean "log_b(s/t)", then, yes, the "expanded" form would be "log_b(s) - log_b(t)".

convert logn T=-x to an expoenetial equation Is this n-x=T???

There are no exponents in your answer, which should tip you off that there may be a problem here.

Use the relationship between logs and exponents:

. . . . ."y = log_b(x)" is the same as "x = b^y"

Eliz.

 

[soroban]

Hello, Elaine!

Express log_b(s/t) as a difference of logarithms

Is this solution: log_b(t) - log_b(s) ? . . . . no

You have it backwards.

It is: . log_b(numerator) - log_b(denominator)

Convert log_n(T) = -x to an expoenetial equation

Is this: n^-x = T ?

If that is what you meant to write, it's correct.

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

You can write " x squared" as x^2

With "x to the two-thirds", it's best to write: x^(2/3)
. . If you write: x^2/3, it could be read x²/3 . . . or x^2/3