s quare both sides?

g1sk8terz

New member
Joined
Sep 8, 2005
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10
hi here's my problem: root of x + x = 1


should i subtract x from both sides
then square both sides?

if so, then should i square (1-x) or 1 squared minus x squared?
 
Your formatting is ambiguous. Is the "root" a square root? A cube root? Something else? Is the first "x" included in the root, or are both x's included?

Please reply with clarification, showing the steps you have tried. Thank you.

Eliz.
 
sorry here it is again


(square root of x) + x = 1

solve for x

(square root of x) = 1 - x

and then i square both sides....to get x = ...
now there's my problem. should i square the expression (1-x)
or should i just do SQUARE 1 - SQUARE x
 
Thank you for your reply.

You have:

. . . . .sqrt(x) + x = 1

. . . . .sqrt(x) = 1 - x

. . . . .[sqrt(x)]<sup>2</sup> = (1 - x)<sup>2</sup>

. . . . .x = 1 - 2x + x<sup>2</sup>

. . . . .0 = 1 - 3x + x<sup>2</sup>

. . . . .x<sup>2</sup> - 3x + 1 = 0

Apply the Quadratic Formula. Remember to check your solutions in the original problem, to make sure neither of them gives you a negative inside the radical.

Hope that helps a little. :D

Eliz.
 
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