Please Help

Is there a question, or did you just want us to know that?

You could try a little harder to express logs of various bases.

Have you considered a change of base?
 
Oh, well in that case, have you considered a change of base? Base 2 looks like it would be helpful.
 
If the expression is log<sub>8</sub>((1/2)<sup>1/4</sup>), then take the 1/4 out front (using one of the log rules you've learned), then figure out the power that turned 8 = 2<sup>3</sup> into 1/2. (Hint: Think about negative and fractional exponents.)

Then multiply this number by the 1/4.

Eliz.
 
hotvicky said:
log 8 of (1/2)^(1/4)
Click to expand...
Same idea, but slightly different pathway:

log<sub>8</sub>(½<sup>¼</sup>) =
¼*log<sub>8</sub>(½) =
¼*log<sub>8</sub>(2<sup>-1</sup>) =
-¼*log<sub>8</sub>(2) =
-¼*[log<sub>2</sub>(2)]/[log<sub>2</sub>(8)] =
-¼*[1]/[log<sub>2</sub>(2<sup>3</sup>)] =
-¼*[1]/[3] =
-1/12

One step at a time. You do NOT have to see the end of the problem before you get started. Jump right in. You can't break it.
 
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