Quickie on Simple problem, I'm confused ><

No, our diagrams are just shockingly out of scale!

Look at my modified picture:

The length from O to the middle of WZ is 2.5. Half the length of WX which was 5.

The length from the midpoint of WZ to that of BC is 1+1=2. This is from the width of the squares we were given.

So the length of the red dashed line is 2+2.5=4.5

The triangle ABC folds over BC to O, so its height is 4.5 also.

So, height of ABC = 4.5. Length of its base, BC, = 3.

The formula for the area of a triangle is
\(\displaystyle \L A = \frac{1}{2} bh\)

where \(\displaystyle b\) is the length of its base, and \(\displaystyle h\) is its height.

Is this making any sense?
 
Denis (to himself): "if the purpose of this problem is to show students
how to calculate the area of a triangle, then why oh why did the teacher
not simply state: triangle ABC has base BC = 3 and height from A to BC = 4.5;
what is ABC's area? " :idea:
 
I thought it may be to prepare students for the bad diagrams the teacher is going to draw in upcoming tests.
 
Unco said:
I thought it may be to prepare students for the bad diagrams the teacher is going to draw in upcoming tests.
:lol: That's funny! :twisted:

Eliz.
 
I do believe the answer is 6.75^2

base = 3

height= 4.5

4.5 x 3=13.5

13.5/2=6.75^2 :D
 
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