The lines l1 and l2 have vector equations
r= (1,-2,3) + t(0,2,1)
r= (1,0,4)+ s(1,-2,1)
respectively for some real parameters t and s
i) Find the acute angle between the two lines l1 and l2. => I have solved this and found the result which is 56.8 degree
ii) Show that l1 passes through point P (1,-4,2)=> Done too!
Hence, show that the distance between point P and any point on the line l2 is given by square root of (6s^2-12s+20). Deduce the shortest distance between point P and line l2.
This part gets confusing since i dont know how to find the general formula of the distance of point P and points on l2? If I can find out the result, then the shortest distance is square root of 14.
I hope someone can help me out
r= (1,-2,3) + t(0,2,1)
r= (1,0,4)+ s(1,-2,1)
respectively for some real parameters t and s
i) Find the acute angle between the two lines l1 and l2. => I have solved this and found the result which is 56.8 degree
ii) Show that l1 passes through point P (1,-4,2)=> Done too!
Hence, show that the distance between point P and any point on the line l2 is given by square root of (6s^2-12s+20). Deduce the shortest distance between point P and line l2.
This part gets confusing since i dont know how to find the general formula of the distance of point P and points on l2? If I can find out the result, then the shortest distance is square root of 14.
I hope someone can help me out