F faith14 New member Joined Nov 24, 2007 Messages 7 Nov 24, 2007 #1 4(2y-1) = -8(.5-y) When I solve this equation I get: 8y - 4 = -4 + 8y then if I subtract 8y from both sides of the equation I end up with -4 = -4 Does this mean there is no solution to this problem? Or, am I doing something wrong? Thanks!

4(2y-1) = -8(.5-y) When I solve this equation I get: 8y - 4 = -4 + 8y then if I subtract 8y from both sides of the equation I end up with -4 = -4 Does this mean there is no solution to this problem? Or, am I doing something wrong? Thanks!

J jwpaine Full Member Joined Mar 10, 2007 Messages 723 Nov 24, 2007 #2 Re: 4(2y-1) = -8(.5-y) It means that it is a true statement: both sides are equal \(\displaystyle 4(2y-1) = -8(.5-y)\) \(\displaystyle 8y-4 = -4+8y\) \(\displaystyle 8y = 8y\) \(\displaystyle y = y\)

Re: 4(2y-1) = -8(.5-y) It means that it is a true statement: both sides are equal \(\displaystyle 4(2y-1) = -8(.5-y)\) \(\displaystyle 8y-4 = -4+8y\) \(\displaystyle 8y = 8y\) \(\displaystyle y = y\)