Solving Radical Equations

G

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1. 8/(x+4) +1 = 5x/(x^2-2x-24)

2. 2x(x+3) - x/(x+7) = (x^2-1)/(x^2+10x+21)

Any one able to show me where to start after figuring out the LDC would be my hero for the day!

The LDC for 1 is (x-6)(x+4)
and far 2 it's (x+3)(x+7) correct?
 
First ones answer is x= 8 and -9...corret ??? but the other one I can get anywher with is at alk..
I get this
(2x)(x+7) - (x) (3+3) = (y^2 -1)
then I get (2x^2 +14 x)(x-3x) = (y^2 -1) but then I keep getting zero on both side???? Help please!!!
 
I keeep getting zero'd out on both sides?

2x(x+7) - (x) (x+3) = (x^2 -1) so
(2x^2 +14x) - ( x^2 -3x) = (x+1)(x-1) then
(x^2 +11x)= (x^2 -1)
(0+12x)=0
??????
What am I doing wrong???? Help Please!! :cry: :cry: :? :x :cry:
 
Re: I keeep getting zero'd out on both sides?

Your last step should be \(\displaystyle 11x = -1\).
 
Thanks so much!

I kept getting that but thought I should still have an x^2 or a even division?? Your me hero this mornng! I've been working on this problem since 1 am this morning as my son had all the rest right but this one....he went to school to have his teacher help him but it would have driven me crazy to wait all day to see what the answer was! Thanks again! Mom
 
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