Broken Watch: I know the watch stopped 21 mintues ago, so

G

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I was recently given a new watch for my birthday. However, as usual with my presents, it was quite useless as it loses 6 minutes every hour. I set it using my friend's accurate watch at midnight and it now shows 10:39am. I know that the watch stopped 21 mintues ago so what is the correct time now?
 
What time is it? Time to go get your watch fixed :shock:

Hint: at noon, your watch would show 10:48 had it not stopped at 10:39.
 
So...
10:39+21 minutes=11:00 right?
That seemed easy. Or was there a catch?
 
Goistein said:
So...
10:39+21 minutes=11:00 right?
That seemed easy. Or was there a catch?
Go read the problem again, Goistein:
10:39 is the time according to faulty watch, so it's NOT 10:39 :idea:
 
You just have to turn it into an algebra problem.
(I am assuming that the lost time happens gradually as the hour goes as opposed to the change happening instantantly each hour.)

Broken watches time = BT
Real time = RT
Time loss = TL

The broken watches time equals(BT) the real time(RT) minus 6 minutes for every hour that passes.
If you write this as an algebraic equation

BT=RT-TL*RT you know BT=10:39 or 10+(39/60)=10.65
and TL=6 minutes or 6/60=.1
10.65=RT-.1*RT bring together like terms
10.65=.9*RT divide both sides by .9
11.8333=RT 11.833333 = 11:50

Do not forget to add the 21 minutes that already passed.

the current time is 12:11
 
chapdawg147 said:
You just have to turn it into an algebra problem.
Please note: Since this was posted to the "Arithmetic" category, the assumption has been made that the student has not yet reached algebra, or even pre-algebra. The tutors replied within the given context.

Thank you.

Eliz.
 
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