graphing linear equations by using the slope method

[Guest]

My workbook says that I need to "Graph each linear equation by using the slope method". This is what i have so far:

equation: x - 4y = 8

1) The slope of x - 4y = 8 is m = -1/4, because m = -A/B = -1/4 <--is this right?

2) If x = 0, then x*0 - 4y = 8; y = -2. Therefore, the point (0, -2) is the solution of the equation x - 4y = 8

If you could help me, then that would be great! Thanks

 

[arthur ohlsten]

I will do yhe problem with a method I am familiar with
equation of a line:
y=mx+b

eq1)
x-4y=8
-4y=-x+8 multiply both sides by -1
4y=x-8
y=1/4 x -2 slope m = 1/4

the answer is + 1/4

Ax+By=C
A=1
B=-1/4
m=-A/B
m=-1/[-4]
m=1/4
==============================================
2)
I do not know what you are trying to find.
x-4y=8
-4y=-x+8 multiply both sides by -1
4y=x-8
y=1/4 x -2 a straight line slope 1/4
y intercept, or the point the line crosses the y axis, is when x=0
let x=0 then
y=-2

We have a straight line , slope 1/4 passing thru the point 0,-2
to draw the line I would use the two points x=0 y=2 and x=4 y=-1

This equation has no solution. The equation has 2 unknowns. Every point on the line defined above satisfys the equation. An infinite number of solutions
Arthur