y^3 dy/dx = (y^4 + 1) cos x
so I separate the variables:
y^3 / (y^4 +1) dy = cos x
integrate both sides:
1/4 ln(y^4 +1) = sin x
Can anyone explain to me why the integration of y^3 / (y^4 +1) = 1/4 ln(y^4 +1)
I can see that the integral of 1/(y^4 + 1) = ln(y^4 + 1) but I don't get the 1/4 part.
I kno it has something to do with the substitution rule...but i don't remember that very well
thanks!
so I separate the variables:
y^3 / (y^4 +1) dy = cos x
integrate both sides:
1/4 ln(y^4 +1) = sin x
Can anyone explain to me why the integration of y^3 / (y^4 +1) = 1/4 ln(y^4 +1)
I can see that the integral of 1/(y^4 + 1) = ln(y^4 + 1) but I don't get the 1/4 part.
I kno it has something to do with the substitution rule...but i don't remember that very well
thanks!