discontunity rule says if a function breaks at certain point , then that point is discontinuity point.

Example : y=1/x if, x=0 ...y breaks , so x=0 is a point of discontinuity.

Now with this idea, lets us try ,

f(x)=(x^2-64/x+8)

= x-8

this can never break for any real value of x ...right ? so this function cant be having discontinious point ....am i right ?

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