defeated_soldier
Junior Member
- Joined
- Apr 15, 2006
- Messages
- 130
discontunity rule says if a function breaks at certain point , then that point is discontinuity point.
Example : y=1/x if, x=0 ...y breaks , so x=0 is a point of discontinuity.
Now with this idea, lets us try ,
f(x)=(x^2-64/x+8)
= x-8
this can never break for any real value of x ...right ? so this function cant be having discontinious point ....am i right ?
Example : y=1/x if, x=0 ...y breaks , so x=0 is a point of discontinuity.
Now with this idea, lets us try ,
f(x)=(x^2-64/x+8)
= x-8
this can never break for any real value of x ...right ? so this function cant be having discontinious point ....am i right ?