Results 1 to 2 of 2

Thread: Indeterminate? lim [t->infty] [-(t 2^(-t)) / ln(2)]

  1. #1

    Indeterminate? lim [t->infty] [-(t 2^(-t)) / ln(2)]

    [tex]\L \lim_{t\to +\infty} -\frac{t2^{-t}}{\ln{2}}[/tex]
    is this just equal to zero? or will i still evaluate it using LHR

    i think so
    [tex]\L -\frac{\infty}{2^{\infty}\ln2}[/tex]

    using LHR:
    [tex]\L \lim_{t\to +\infty} -\frac{t}{2^{t}\ln{2}}[/tex]
    [tex]\L \lim_{t\to +\infty} -\frac{1}{2^{t}(\ln2)^2}[/tex]
    [tex]\L = 0[/tex]

  2. #2
    Elite Member
    Join Date
    Sep 2005
    You're right, Adam. It's 0


Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts