(4x/5-2y)-2(2x+7/3y)
(4x/5-2y)-2(2x+7/3y)
WHAT is your question? I see no fractions in your expression.
I'm just an imagination of your figment !
Originally Posted by Mish88
I don't see any fractions here, either!
Multiply each term inside the second set of parentheses by -2, and then combine like terms.
Please show us your work on this problem so we can see where you might be making a mistake.
(4x/5-2y)-2(2x+7/3y) is [tex](\frac{4x}{5}-2y) - 2(2x + \frac{7}{3y})[/tex]. Is that what is meant?
yes that is the way but how do you write it like that it would be a big help if you could teach me.Thanx
To learn how to post in LaTeX, try following the relevant links in the "Forum Help" pull-down menu at the very top of every forum page.Originally Posted by Mish88
Have fun!
Eliz.
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