Solve the following initial value problem: y'' - 10y' + 9y= 5t , y(0) = -1, y'(0)=2 using the laplace transform formula, i get this--- s^2 Y * sy(0) - y'(0) - 10[sY - y(0)] + 9Y = 5/s^2 how do i figure out what y(0) and y'(0) is? thanks