Hey guys, I need help with this one. I can't figure out what c1 and c2 are equal to.
y'' + y' - 2y = 0
y(0) = 1, y'(0) = 0
This is what I did:
r^2 + r - 2 = 0
(r+2)*(r-1) = 0
r = -2 and 1
So, y(t) = c1exp(-2t) + c2exp(t)
y(0) = 1 = c1 + c2
y'(0) = 0 = 2c1 + c2
So, now how do I find what c1 and c2 are equal to?
Thanks for any help.
y'' + y' - 2y = 0
y(0) = 1, y'(0) = 0
This is what I did:
r^2 + r - 2 = 0
(r+2)*(r-1) = 0
r = -2 and 1
So, y(t) = c1exp(-2t) + c2exp(t)
y(0) = 1 = c1 + c2
y'(0) = 0 = 2c1 + c2
So, now how do I find what c1 and c2 are equal to?
Thanks for any help.