# 6/w-2 + 9w/w2-7w+10

#### deanamarie77

##### New member
6/w-2 + 9w/w2-7w+10

well I factored the w2-7w+10 and got (w-5)(w-2)

so i figured the w-2 cancelled eachother out and I was left with 6 +9w/w-5

#### stapel

##### Super Moderator
Staff member
deanamarie77 said:
6/w-2 + 9w/w2-7w+10
I'm going to guess that the above means the following:

. . . . .6/(w - 2) + (9w)/(w^2 - 7w + 10)

(This could also be formatted as follows....)

. . . . .$$\displaystyle \L \frac{6}{w\,-\,2}\, +\,\frac{9w}{w^2\,-\,7w\,+\,10}$$

And I will assume that the instructions were to "simplify".

deanamarie77 said:
I factored the w2-7w+10 and got (w-5)(w-2)
so i figured the w-2 cancelled eachother out
Since there is no "w - 2" factor in the numerator of the second fraction, there is nothing to cancel out.

Instead, so add the fractions, convert them to the common denominator of (w - 2)(w - 5). Then add the numerators, combine "like" terms, and, if possible, factor. Then see if anything cancels.

Eliz.

#### tkhunny

##### Moderator
Staff member
deanamarie77 said:
6/w-2 + 9w/w2-7w+10

well I factored the w2-7w+10 and got (w-5)(w-2)

so i figured the w-2 cancelled eachother out and I was left with 6 +9w/w-5

1) You went wrong when you tried to write the problem statement. It is very, very difficult to understand what you mean.