1lessdigit
New member
- Joined
- Nov 1, 2009
- Messages
- 1
I need to solve the following diff eq: T dH/dt + H = K Q to develop an expression to define H as a function of t
where
H = height of liquid level in tank
Q = flow rate
K = not sure
initial conditions:
H=0
T= 30
K= 0.4
Q= 2
I have set the homogeneous equation T dH/dt + H = 0, and separated the variables to get: dH/H = -(1/T) dt , integrated both sides to get H= exp (-t/T) + exp (c) which yields C1 exp(-t/T)
I'm not sure how to treat KQ
Please help.
Thanks
where
H = height of liquid level in tank
Q = flow rate
K = not sure
initial conditions:
H=0
T= 30
K= 0.4
Q= 2
I have set the homogeneous equation T dH/dt + H = 0, and separated the variables to get: dH/H = -(1/T) dt , integrated both sides to get H= exp (-t/T) + exp (c) which yields C1 exp(-t/T)
I'm not sure how to treat KQ
Please help.
Thanks