"Fitting a Line to Data"

stumpedstudent

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Jan 21, 2010
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My final is tomorrow and I am trying despretly to study but I seem to have forgotten everything.
Here's my problem:
"Write an equation in point-slope form for each line."
a. parallel to y=7-4x and passing through (2, -5)

I thought it might be y=2-5x, however, I have no recollection of ever actually learning this. Could someone tell me if I am doing this completely wrong or not?

Thankyou
 
stumpedstudent said:
My final is tomorrow and I am trying despretly to study but I seem to have forgotten everything.
Here's my problem:
"Write an equation in point-slope form for each line."
a. parallel to y=7-4x and passing through (2, -5)

I thought it might be y=2-5x, however, I have no recollection of ever actually learning this. Could someone tell me if I am doing this completely wrong or not?

Thankyou

The slope of y = mx + c is m, and the intercept is c. Parallel lines have the same slope. Therefore, a line parallel to y=-4x+7 will be y=-4x+c for some c. You can find c by substituting your point (x,y)=(2,-5), but I think the problem is easier than that :

I *think* 'point-slope' form is when you write y-y0 = m(x-x0), where m is the slope, and (x0,y0) is a point on the line. Then, the equation you want here is y-(-5) = -4(x-2), or y+5=-4(x-2)

y-(-5) = -4(x-2), since your point is (2,-5)
y-(-5) = -4(x-2), since your point is (2,-5)
y-(-5) = -4(x-2), since the slope is -4, since it is parallel to y=-4x+7
 
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