\(\displaystyle u = 2x+y, du=1dy\)
\(\displaystyle \int_3^4 (2x+y)^{-2} dy = -u^{-1} = -(2x+y)^{-1} |^{^{y=4}}_{_{y=3}} = \frac{1}{(2x+3)(2x+4)}\)
For the outer integral, simply use a partial fraction decomposition. It will have two natural log answers.