College algebra 1

[Cyndi]

Please help me pass my final; I have 4 more I need solved ASAP! Sorry about the 11th hr thing, just discovered ya'll. OK, here they are:

1) graph the equation using the slope and the y-intercept: y=7/6x+3

2) solve the following system of equations: x+3y=2 (1)
x=8-3y (2) The solution is ______________; There is no solution________

3)find the indicated outputs for f(x)=3x2-4y: f(0)=_______
f(-1) = _______
f (2) = _________

4) solve for the indicated letter; d=6e, for e


THANK YOU SO MUCH PEOPLE, if I get these solved by tomorrow I have a chance of passing this class. At this stage in the game I cannot afford to fail!!
I appreciate all the help I can get.

Cyndi

 

[Denis]

Those 4 problems are VERY EASY.
What will giving you the answers accomplish?
Btw, homework not done here.
I'm just a "helper" here; perhaps the moderators will think otherwise...

 

[masters]

Please help me pass my final; I have 4 more I need solved ASAP! Sorry about the 11th hr thing, just discovered ya'll. OK, here they are:

1) graph the equation using the slope and the y-intercept: \(\displaystyle y=\frac{7}{6}x+3\)[\quote]

To graph this, know that the equation is in the form \(\displaystyle y=mx+b\) where m = slope and b = y-intercept.

Graph the y-intercept at (0, 3).

From there use the slope to find a second point. You do this by translating up 7 units and right 6 units. Graph this point and draw your line through them.

2) solve the following system of equations:

[1] \(\displaystyle x+3y=2\)

[2] \(\displaystyle x=8-3y\)

The solution is ______________; There is no solution________

First, change equation [2] to be in the same form as [1].

[1] \(\displaystyle x+3y=2\)

[2] \(\displaystyle x+3y=8\)

You should notice that if we subtract the two equations we would end up with \(\displaystyle 0=-6\) which is a false statement. This means the two lines are parallel and therefore inconsistent. They do not intersect. Their slopes are the same. There is no solution.

3)find the indicated outputs for \(\displaystyle f(x)=3x^2-4y\)

f(0)=_______
f(-1) = _______
f(2) = _________

Are you sure about this function. Is it really \(\displaystyle f(x)=3x^2-4y\).

4) solve for the indicated letter; d=6e, for e

\(\displaystyle d=6e\)

Simply divide both sides by 6.

THANK YOU SO MUCH PEOPLE, if I get these solved by tomorrow I have a chance of passing this class. At this stage in the game I cannot afford to fail!!
I appreciate all the help I can get.

Cyndi

 

[Cyndi]

Yes, I am sure it is f(x)=3x2-4y 3x2sq

These all may be easy for you but they are confusing for me, an older woman trying to get a degree that has not had algebra in 47 years. I appreciate all the help I can get. I am desperate to pass this class.

Thanks to all that reply.

Cyndi

 

[mmm4444bot]

\(\displaystyle f(x) \;=\; 3x^2 \;-\; 4y\)

f(x) is interpreted as a single symbol. It is a variable, just like x.

f(x) represents what comes out of the function f (defined above) when we input something (represented by x).

Look at the definition: 3x^2 - 4y

It literally shows us what function f does to its inputs.

First, it squares them.

Then, it multiplies the result by 3.

Finally, it subtracts 4y.

The final result is spit out, and we refer to this output as "f(x)".

In this exercise, we cannot evaluate the variable f(x) for any Real number that we might input for x because we don't know what the symbol y represents.

EG 1:

f(4) represents the output from function f, when we input 4.

First, it squares 4.

Then, it multiplies the result by 3.

Finally, it subtracts 4y.

f(4) = 3(4)^2 - 4y

f(4) = 3(16) - 4y

f(4) = 48 - 4y

EG 2 (symbolic):

Let's take some unknown constant (I'll call it "C"), and multiply it by -1, and then input the result into function f, to see what comes out.

In other words, let's determine f(-C).

f(-C) = 3(-C)^2 - 4y

= 3(C^2) - 4y

= 3C^2 - 4y

Are these exercises from some on-line "class" ?