intermediate algebra

[hopen2impov]

divide

(8x^2 +65x -63) / (x+9)

x+9/(x+9)(8x-7)
1/8x-7 if this is not right, please show me in steps so i can practice and study it.

 

[wjm11]

divide

(8x^2 +65x -63) / (x+9)

x+9/(x+9)(8x-7)
1/8x-7 if this is not right, please show me in steps so i can practice and study it.

Why did you invert the original problem?

Your factoring and simplifying were correct.

(8x^2 +65x -63) / (x+9) = (x+9)(8x-7)/(x + 9) = 8x - 7

 

[lookagain]

divide

(8x^2 +65x -63) / (x+9)

x+9/(x+9)(8x-7)
1/8x-7 if this is not right, please show me in steps so i can practice and study it.

hopen2impov,

despite that you should not have inverted, if you're going to type the bottom two expressions
(or ones similar to it), use grouping symbols in the numerator and the denominator of the second
expression, and use grouping symbols in the denominator of the third (last) expression:

\(\displaystyle (x + 9)/[(x + 9)(8x - 7)]\)

\(\displaystyle 1/(8x - 7)\)

 

[hopen2impov]

ok, i will keep this in mind but i 'm glad i got it right, well, some what! Thank you, i wish i had your brain