hopen2impov
Junior Member
- Joined
- Aug 4, 2010
- Messages
- 66
solve using the five step problem solving process, translate, reword, carry-out, check, and state.
An object altitude, in meters is given by the polynomial ht+vt-9.8t^2 where h is the height in meters from which the launch occurs. v is the initial upward speed in meters per second and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second. How high above ground will the peble be after 3 seconds. (round to the nearest tenth of a meter).
ht +vt -9.8t^2
h=164 meters + vt=36(3) -9.8t^2
h=164 meters + 108 -9.8t^2
h=164 meters +172 meters -9.8t^2
answer 163.8t^2 i do not know this but i hope i'm right
An object altitude, in meters is given by the polynomial ht+vt-9.8t^2 where h is the height in meters from which the launch occurs. v is the initial upward speed in meters per second and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second. How high above ground will the peble be after 3 seconds. (round to the nearest tenth of a meter).
ht +vt -9.8t^2
h=164 meters + vt=36(3) -9.8t^2
h=164 meters + 108 -9.8t^2
h=164 meters +172 meters -9.8t^2
answer 163.8t^2 i do not know this but i hope i'm right