1. ## Re: Re:

Originally Posted by Subhotosh Khan

$a\div bc$ is same as a\(bc)

So in other words it seems to me you're saying after a $\div$ sign you automatically assume there is brackets around any terms that follow to find the correct answer...??

Which means:

$(-5a^3b^5)^2 \div a^4b^3 =$ (-5a^3b^5)^2 / (a^4b^3) = $25a^2b^7$

Correct?

P.S. I apologize for thinking that $\div =$ / I know im not here to argue but sometimes you argue in order to be proved wrong so you can understand where your understanding/argument was flawed. And therefore you come to understanding. You guys have ZERO patience for someone who is a noob and trying to understanding. Of course im not trying to argue that convention is wrong and needs to be changed. But im obviously confused or else i wouldnt be asking for more help! But if you are so frustrated by such an idiot who's honestly trying to understand and is honestly confused then simply dont reply.

2. ## Re: Re:

Originally Posted by einstein
You guys have ZERO patience for someone who is a noob and trying to understanding.
Don't generalize to all of the posters; that is exaggerating.

Originally Posted by einstein
But if you are so frustrated by such an idiot who's honestly trying to understand
and is honestly confused then simply dont reply.

$And \ about \ this \ answer \ supposing \ to \ be \ negative \ from$

$\ the \ book&#39;s \ answer \ section, \ I \ could \ likely \ only \ see$

$\ that \ if \ the \ problem \ were \ actually \ stated \ as$

$\ -(5a^3b^5)^2 \ \div \ a^4b^3, \ or$

$-(-5a^3b^5)^2 \ \div \ a^4b^3, \ or$

$(5a^3b^5)^2 \ \div \ -a^4b^3, \ or$

$(-5a^3b^5)^2 \ \div \ -a^4b^3$

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