robert.miller
New member
- Joined
- Aug 12, 2011
- Messages
- 3
Annual profit in thousands of dollars is given by the function, P(x) = -.1x2 + 50x - 300, where x is the number of items sold, x ≥ 0.
find the profit for 5 different values of x
To find the five different profit values for x with the +50x determining the variable expense and the -300 representing the fixed cost. Would I change the variable cost to another number in order to find five different values of x?
I have been substituting for x and I continue to come up with a negative value for x.
I do not understand what I am doing wrong.
What I have done:
Note: ^2 is the best I can do for squared.
P(x) = R(x) - c(x)
= -.1x^2 + 52 (4x) - (300,000.00 + 50,000x)
= -.1x^2 + 208x - 300,000.00
= -299,844.50 when 5 products are sold annually
find the profit for 5 different values of x
To find the five different profit values for x with the +50x determining the variable expense and the -300 representing the fixed cost. Would I change the variable cost to another number in order to find five different values of x?
I have been substituting for x and I continue to come up with a negative value for x.
I do not understand what I am doing wrong.
What I have done:
Note: ^2 is the best I can do for squared.
P(x) = R(x) - c(x)
= -.1x^2 + 52 (4x) - (300,000.00 + 50,000x)
= -.1x^2 + 208x - 300,000.00
= -299,844.50 when 5 products are sold annually
