W =

minnsy229

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Jun 20, 2012
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Combine the following two equations to give an equation for W which does not involve g.

Equation (1): W = mg

Equation (2): s = 1/2gt^2
Give your answer in the simplest form and without brackets. Use the '/' key and/or the superscript box to format your answer, as appropriate.

W =
 
Better try that again. What did you get for 'g' out of the second equation?

Where did 's' go?
 
so it should be 1/2mt^2 ????

No. What Denis meant is use equation 2 to solve for g and then substitute that formula into equation 1.

\(\displaystyle \displaystyle s=\frac{1}{2}gt^2\)

\(\displaystyle \displaystyle 2s=gt^2\)

\(\displaystyle \displaystyle \frac{2s}{t^2}=g\)

Now, substitute this formula for g into the first equation.
 
mmmmm

so, 2ms/t^2 ?


No. What Denis meant is use equation 2 to solve for g and then substitute that formula into equation 1.

\(\displaystyle \displaystyle s=\frac{1}{2}gt^2\)

\(\displaystyle \displaystyle 2s=gt^2\)

\(\displaystyle \displaystyle \frac{2s}{t^2}=g\)

Now, substitute this formula for g into the first equation.
 
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