wood chips: 282.8 grams of chips in sample, baked for 1 hr; lost 11 gm water

tim/conserv

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I operate a biomass mill , twice a day I take a sample of wood chips to dertermine the % of
moisture in the chips --sample measured 282.8 grams of chips in sample ,baked it for one hour
and lost 11 grams of weight in moisture ,is that 11% moisture lost? if there is more moisture still
in chips then what percentage is that?
 
... --sample measured 282.8 grams of chips in sample ,baked it for one hour
and lost 11 grams of weight in moisture ,is that 11% moisture lost?


if there is more moisture still in chips then what percentage is that?



That depends. If there were 100 grams of moisture in the 282.8-gram sample.
then it would be 11% percent moisture lost from the original number of grams
of moisture.


But, if there are fewer than or more than 100 grams of moisture in the
282.8-gram sample, then it would not represent 11% of the number of grams of
original moisture lost.


As concerned with your first question, there is not enough information.
 
I operate a biomass mill , twice a day I take a sample of wood chips to dertermine the % of
moisture in the chips --sample measured 282.8 grams of chips in sample ,baked it for one hour
and lost 11 grams of weight in moisture ,is that 11% moisture lost? if there is more moisture still
in chips then what percentage is that?
'
No, 11 grams out of 282.8 grams is not 11%. That is, rather, 11/282.8= 0.0389 grams of moisture per gram of wood, and 0.0389(100)= 3.9 grams of moisture per hundred grams which is 3.9 per cent. As to whether there is still more moisture in the wood, that is impossible to tell based on what is given here.
 
'
No, 11 grams out of 282.8 grams is not 11%.


Here is what my post was answering. This was stated "...and lost 11 grams of weight in moisture,
is that 11% moisture lost?"


There are 282.8 grams of wood chips, that consists of an unknown mass of dry wood chips
combined with an unknown mass of moisture.


That would mean the OP is asking whether the 11 grams of moisture lost, compared to the
original number of grams of moisture, is 11%. And I stated that cannot be determined because
the number of grams of the original moisture cannot be determined.


I did not see the OP asking if 11 grams of moisture out of 282.8 grams
(of dry wood chips and moisture combined) would be 11%.



If the OP meant that, then it needs to be corrected/clarified by him/her.
 
Back working weight from moisture percentage

Hi, im hoping someone can help me with this percentage equation.

I have 450kg of woodchip which has 10% moisture. I know the woodchip had a 55% moisture before drying. What is the original weight of the wet woodchip?

If someone can help me out with this i would be very greatful

Cheers
 
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