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Thread: Calculate asymptotes and local extreme values

  1. #1

    Calculate asymptotes and local extreme values

    I'm fed up with this question from my book. I've calculated the constants to this equation but got stuck at the asymptotes and local extreme values calculations which I need to plot the graph, perhaps anyone could help me out or guide me towards the solution of calculating the asymptotes/local extreme values and then to plot the graph.


    Equation:


    Define the constants A,B,C so that a function which is defined by

    f(x) =
    (1) (6/pi) arctan(2-(x+2)˛) when x < -1
    (2) x + c* |x| - 1 when -1 ≥ x ≥ 1
    (3) (1/Ax+B) + 4 when x > 1 och Ax + B ≠ 0


    is continuous at x = -1 and differentiable in x = 1


    _______________


    I calculated the constants, A,B,C to:


    A = -18


    B = 16


    C = 7/2


    Any help is appreciated,


    Thanks, Michael.

  2. #2
    Elite Member
    Join Date
    Jun 2007
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    Quote Originally Posted by 1Michael1 View Post
    I'm fed up with this question from my book. I've calculated the constants to this equation but got stuck at the asymptotes and local extreme values calculations which I need to plot the graph, perhaps anyone could help me out or guide me towards the solution of calculating the asymptotes/local extreme values and then to plot the graph.


    Equation:


    Define the constants A,B,C so that a function which is defined by

    f(x) =
    (1) (6/pi) arctan(2-(x+2)˛) when x < -1
    (2) x + c* |x| - 1 when -1 ≥ x ≥ 1
    (3) (1/Ax+B) + 4 when x > 1 och Ax + B ≠ 0


    is continuous at x = -1 and differentiable in x = 1


    _______________


    I calculated the constants, A,B,C to:


    A = -18


    B = 16


    C = 7/2


    Any help is appreciated,


    Thanks, Michael.
    Are you sure you have posted the domains correctly?

    Please review your post - very carefully - and make necessary corrections. We do not want to waste time and effort on the wrong problem.

    Use a graphing calculator and estimate the answers - then confirm those analytically.
    “... mathematics is only the art of saying the same thing in different words” - B. Russell

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