question relating to hcf,lcm and time and distance with explanation

ragas88

New member
Joined
Jan 19, 2013
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1
Hi All,


Can you please provide me the solutions to the below problems with steps


on how to get the answer for the question below.


I know the below problem is related to HCF or LCM but i am finding it


difficult to implement the concept to get to the solution.




1.At a book store ,MODERN BOOK STORE,is flashed using neon light.The word


is individually flashed at interval 5/2,17/4,41/8 seconds respectively ,and


each word is put off after a second.The least time after which the full name


of the book store can be read again is?




2.A red light flashes 3times per min and green light 5times in 2mins at regular


interval.If both light flashing at the same time,how many time do they flash


together in each hour.


This is a different problem.

3.A train approaches tunnel AB.Inside the tunnel is a cat located at point 3/8th


of the distance AB measured from the entrance A.When the train whistles


the cat runs.If the cat moves to the entrance of the tunnel A the train catches


the cat exactly at the entrance.If the cat moves to the exit ,the train catches


the cat at exactly the exit,B,the speed of the train is greater than the speed


of the cat by what order?


I want the steps and explanation on how you arrived at solution please.


Thanks.
 
Hello, ragas88!

Interesting . . . LCM with fractions.


1. At a bookstore "MODERN BOOK STORE" is flashed using neon light.
The words are individually flashed at intervals \(\displaystyle \frac{5}{2},\,\frac{17}{4},\,\tfrac{41}{8}\) seconds respectively,
. . and each word is put off after a second. .
This phrase is unnecessary.
Find the least time after which the full name of the bookstore can be read again.

\(\displaystyle \text{We have: }\:\text{LCM} \left(\tfrac{5}{2},\,\tfrac{17}{4},\, \tfrac{41}{8}\right)
\;=\; \text{LCM} \left(\frac{20}{8},\,\frac{34}{8},\,\frac{41}{8} \right)\)

. . . . . . . .\(\displaystyle =\;\dfrac{\text{LCM}(20,34,41)}{8} \;=\; \dfrac{13,940}{8} \;=\;1742.5\)


\(\displaystyle \text{Answer: }\:1742.5\text{ seconds} \;=\;29\text{ minutes, }2\!\frac{1}{2}\text{seconds.}\)
 
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