derivative of a function where the arqument has additions

arfie

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Feb 24, 2013
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Hi all..:)

I am a new member here. I am wondering how to take first derivative when the argument(s) has "plus" and "minus" in it.
For example, h=f(y+r-t,p,z). The first argument is (y+r-t). How do I get the first derivative of h w.r.t r (or dh/dr)? Is just the same as having h=f(y,r,t,p,z)?

Thanks,
-Arfie
 
Hi all..:)

I am a new member here. I am wondering how to take first derivative when the argument(s) has "plus" and "minus" in it.
For example, h=f(y+r-t,p,z). The first argument is (y+r-t). How do I get the first derivative of h w.r.t r (or dh/dr)? Is just the same as having h=f(y,r,t,p,z)?

Thanks,
-Arfie

Yes.... when y, r and t are independent of each other
 
Thanks!
How if they're not independent of each other, like h=f(y-r(y,z)+t,p,z)? how to get dh/dr?:confused:

Be careful with these functions!

You do realize that you would take partial derivatives. Now you cannot hold "z" constant as you are varying "r".

If r = g(y,z) then h is not a function of "r" anymore!

Look at the "total differential" - then take the proper partial differential.
 
Be careful with these functions!

You do realize that you would take partial derivatives. Now you cannot hold "z" constant as you are varying "r".

If r = g(y,z) then h is not a function of "r" anymore!

Look at the "total differential" - then take the proper partial differential.


Thanks again, Subhotosh Khan :D!!! very helpful!
 
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