Combining fractions?

Silvanoshei

Junior Member
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Feb 18, 2013
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To make derivatives easier, we tend to simplify fractions and such.

Today I got confused on why (25/t²) - (5/t) became (25-5t/t²) ?
 
When combining fractions a common denominator is required. What would be the common denominator here?

Please show any work you have attempted to solve the problem.
 
To make derivatives easier, we tend to simplify fractions and such.

Today I got confused on why (25/t²) - (5/t) became (25-5t/t²) ?

It doesn't. It becomes (25-5t)/t²


(25-5t/t²) = \(\displaystyle 25 \ - \dfrac{5t}{t^2}\)
 
To make derivatives easier, we tend to simplify fractions and such.

Today I got confused on why (25/t²) - (5/t) became (25-5t/t²) ?
It helps to be careful in the question you pose. You presumably meant (25 - 5t)/t^2 rather than (25 - 5t/t^2). But when you ask questions that are flawed, no one can be sure what you are asking so you may well get answers to a question different from the one you intended.

Guitarguy has it right. You need to remember how to handle algebraic fractions.

\(\displaystyle \dfrac{25}{t^2} - \dfrac{5}{t} = \dfrac{25}{t^2} - \left(\dfrac{5}{t} * 1\right) = \dfrac{25}{t^2} - \left(\dfrac{5}{t} * \dfrac{t}{t}\right) = \dfrac{25}{t^2} - \dfrac{5t}{t^2} = \dfrac{25 - 5t}{t^2}.\)

You probably learned about common denominators in third grade. You can't forget those basics when you are doing calculus. You probably learned about PEMDAS in 6th or 7th grade. You can't forget those basics either.
 
Silvanoshei is correct

To make derivatives easier, we tend to simplify fractions and such.

Today I got confused on why (25/t²) - (5/t) became (25-5t/t²) ?

You showed your work: you said you were confused.
You worded it correctly: if you indeed saw (25/t²) - (5/t) become (25-5t/t²)
Then you had good reason to be confused. As Jeff points out, it is wrong.

Another approach, not using a common denominator.

Let A=25/t/t - 5/t
Multiply both sides by tt
Att = 25 - 5t
Divide both sides by t
A = (25 - 5t)/t
Divide both sides by t
A = (25 - 5t)/t/t
 
You showed your work: you said you were confused.
You worded it correctly: if you indeed saw (25/t²) - (5/t) become (25-5t/t²)
Then you had good reason to be confused. As Jeff points out, it is wrong.

Another approach, not using a common denominator.

Let A=25/t/t * - 5/t
Multiply both sides by tt
Att = 25 - 5t
Divide both sides by t
A = (25 - 5t)/t
Divide both sides by t
A = (25 - 5t)/t/t*

* I would be confused if I were to be learning this for the first time if I had to deal with the
complex fractions presented to me here.



Instead, keep it simpler looking and have fewer steps:

Let A = 25/t^2 - 5/t

Multiply both sides by t^2:

At^2 = 25 - 5t

Divide both sides by t^2:

A = (25 - 5t)/t^2

Done.

- - - - - -

As well as an answer in this exercise wouldn't be given to the instructor
with a complex fraction it. That's what the "^" is there for (again) to
take care of that (other than using Latex or something similar).
 
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All my trips to the corner have been successful:
I learned something from my mistakes.
Soooo the ones who never go never learn anything:rolleyes:
Hmmm. I have never learned anything when denis was in the corner with me because he keeps making funny faces and jokes. So the question is when does he have time to learn anything?
 
Lookagain,
The extra step was added specifically with you in mind because if someone does not know that tt=t^2,

they may also not understand what x/t/t represents.

The student needs to know prior to this problem that tt = t^2. If not, then the student is in the wrong
class, or needs remedial work to catch up in that class.

You have the reasoning backwards.

Let's put aside that algebraically that "x/t/t" ** is in awkward form.

It is unreasonable for the student to understand that at the beginning, as you
started your first step uisng the x/t/t kind of idea without showing where it came from.
So then the rest of the steps after that wouldn't matter, because the understanding
would have stopped at that point.
That's akin to the "door in the face" technique. It shuts things down.

However, if you had 1) started with your tt use (and explained why you were using
it instead of t^2), and 2) then explained why you were coming up with the
form of x/t/t, then the motivation for all of the steps to be understood and flow
together would have been there. That route would have been akin to the
"foot in the door" technique. And the foot pushes the door open wider and wider
for continued understanding for the justification of all of the steps.

- - - - - - - - - - -- - - - - - - -




** I'll make the distinction that I am not discouraging this use in general.


A foot/sec/sec (foot per second per second) which is equivalent to \(\displaystyle foot/sec^2\),
has quicker meaning to me, than the one with the exponent of 2 on "sec."
 
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