Find dy/dx:

y=[sin(x+5)]^(5/4)

So far I have this:

y=[sin(x+5)]^(5/4)

y'={[(5/4)cosx(x+5)]^(1/2)} [cos(x+5)] (1)

There are only answers to odd numbered questions in the back of my textbook & this is an even numbered problem. I'm not sure where to go from here or if I've used chain rule the right way.

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