calcstruggles2013
New member
- Joined
- Mar 11, 2013
- Messages
- 6
y = | e3x^2 (8 x5+14)4 |
"Find the derivative."
Lon capa suggests to take the natural log of both sides but I don’t understand how that would help? Bc then you would have
3x^2(8x^5+14)^4 divided by (21x^2 +5x-10)^2
Or would multiplying by the natural log give you
3x^2*4(8x^5+14) divided by 2(21x^2+5x-10)
Also, on the other side wouldn’t you have y’/y so at the end you would have to multiply the right side by the original equation to get y’ alone?
I went about it the second way because I thought it seemed easier and I got an insanely long answer
(((84x+10(6x(32x^5+56))-(42x^2+10x-20)(6(32x&5+56)+6x(160x^4))+((84x+10(160x^4(3x^2))-(640x^3(3x^2)+(6x(160x^4)))(42x^2+10x-20)))*(exp(3x^2)(8x^5+14^4)/(21x^2+5x-10)^2)
I also had my friend try and he got:
(((exp(3*(x^2)))*(8*(x^5)+14)^4)/((21*(x^2)+5x-10)^2))*(6*x+((160*(x^4)/(8*(x^5)+14))+(84*x+10)/(21*(x^2)+5*x-10)))