I need to find the derivative of: f(x)=x[ln(x2+1)]3
From what I understand about the product rule it is: f(x)*g'(x)+f'(x)*g(x)
So I do: x*(3(ln(x2+1)2)*(2x/(x2+1))+(ln(x2+1))3)
and I get:
[(3x(ln(x2+1))2)*2x]/(x2+1)
+ln(x2+1)3
=ln(x2+1)3 +[(6x2(ln(x2+1))2]/[(x2+1)]
---------------------------------------------------------------
But the answer I am supposed to end up with is:
[ln(x2+1)]2
*[ln(x2+1)+((6x2/((x2+1))]
So what did I do wrong ?
Thank you!
From what I understand about the product rule it is: f(x)*g'(x)+f'(x)*g(x)
So I do: x*(3(ln(x2+1)2)*(2x/(x2+1))+(ln(x2+1))3)
and I get:
[(3x(ln(x2+1))2)*2x]/(x2+1)
+ln(x2+1)3
=ln(x2+1)3 +[(6x2(ln(x2+1))2]/[(x2+1)]
---------------------------------------------------------------
But the answer I am supposed to end up with is:
[ln(x2+1)]2
*[ln(x2+1)+((6x2/((x2+1))]
So what did I do wrong ?
Thank you!