Simplifying Combinatorics Question

SDPY15

New member
Joined
May 2, 2013
Messages
17
Hey!

Recently I ran across a really confusing question in my calc lab. (n-3)! (n-1) / n!
So far I was able to simplify the question down to n!-4n+6 which looks a bit like something that I could factor but then I starting running across all of these sites that said you have to have this fancy eq for n!=(n (n-1)!). Would that be applicable here and if so how would I integrate it into my solution? If I'm not on the right track then any help would be appreciated to get me to the proper answer. Thanks!
 
hi

Maybe 1/(n^2 -2n) is an answer
expand denominator n!=n(n-1)(n-2)(n-3)! and simplify.Its easy!!!
Please reply if it is wrong.
 
Top