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Thread: Physics differentiation: moving point has position function

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    Physics differentiation: moving point has position function

    A moving point has a position function (S) and is given by 2D quantities where the (Y) axis is affected by gravity (9.8m/s/s) and (t) is in seconds.

    X(t)=4t cos θ and Y(t)= 4t sin (θ)-5t^2

    If θ = Pi /3 find the speed in directions after 1second

    Find the angle where maximum X direction = maximum Y direction

    Find the time for maximum x direction = maximum Y direction

    Find the acceleration after 2 seconds

    Does the acceleration vary against time?

    Relevant equations/notes....

    Use Equations of linear motion. Eg.

    V= u + at

    S = ut + 1/2 at^2

    V^2 = u^2 + 2as

    9.8m/s/s can be rounded to 10m/s/s for simplicity
    Last edited by stapel; 05-09-2013 at 04:42 PM. Reason: Removing multiple blank lines.

  2. #2
    Elite Member stapel's Avatar
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    Cool

    Quote Originally Posted by JeffGlasgow View Post
    A moving point has a position function (S) and is given by 2D quantities where the (Y) axis is affected by gravity (9.8m/s/s) and (t) is in seconds.

    X(t)=4t cos θ and Y(t)= 4t sin (θ)-5t^2

    If θ = Pi /3 find the speed in directions after 1second

    Find the angle where maximum X direction = maximum Y direction

    Find the time for maximum x direction = maximum Y direction

    Find the acceleration after 2 seconds

    Does the acceleration vary against time?
    How far have you gotten in working through the steps of this exercise?

    Please reply with your work so far, starting with your differentiations with respect to time "t". Thank you!

  3. #3
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    Quote Originally Posted by JeffGlasgow View Post
    A moving point has a position function (S) and is given by 2D quantities where the (Y) axis is affected by gravity (9.8m/s/s) and (t) is in seconds.

    X(t)=4t cos θ and Y(t)= 4t sin (θ)-5t^2

    If θ = Pi /3 find the speed in directions after 1second

    Find the angle where maximum X direction = maximum Y direction

    Find the time for maximum x direction = maximum Y direction

    Find the acceleration after 2 seconds

    Does the acceleration vary against time?

    Relevant equations/notes....

    Use Equations of linear motion. Eg.

    V= u + at

    S = ut + 1/2 at^2

    V^2 = u^2 + 2as

    9.8m/s/s can be rounded to 10m/s/s for simplicity
    You seem to be saying that you have absolutely no idea what this is about! You could see that there is no "g" in this problem can't you? And you title this "Physics differentiation" so you must know that you can find the x and y coordinates of the velocity by differentiating the x and y coordinates of the position function. What do you get when you do that?

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