radical notation

does anyone know how to write 16^-3/4 in radical notation? im stuck on this

I'll do a different but similar problem for you:

\(\displaystyle (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}\)
 
If you consider the factors of 16, the fourth root should be clear.
 
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If you give the factors of 125 some thought, the cube root should be clear.

Her problem is to evaluate \(\displaystyle \displaystyle \left [16\right ]^{\frac{-3}{4}}\).

The problem with 125 was made up by me.
 
does anyone know how to write 16^-3/4 in radical notation? im stuck on this
Claudette, you must use grouping symbols, such as in "16^(-3/4)." Also, for appropriate numbers, as in this case, the expression is equivalent to: \(\displaystyle \ \ \dfrac{1}{(\sqrt[4]{16})^3} \) \(\displaystyle \ \ \ \ \ Continue \ \ with \ \ that.\)
 
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