i tried to answer this question but i dont know if i did was right, and im still really confused, could someone help meCONFUSING question.jpgattempted.jpg
i tried to answer this question but i dont know if i did was right, and im still really confused, could someone help meCONFUSING question.jpgattempted.jpg
Your small and sideways work is too hard for me to follow. Sorry.[tex]\mbox{1. The following system of equations has more than}[/tex]
[tex]\mbox{one solution }\, (x,\, y).[/tex]
. . . .[tex]2ax\, +\, 6y\, =\, 5[/tex]
. . . .[tex]4x\, +\, 3ay\, =\, b[/tex]
[tex]\mbox{The value of }a\, +\, b\mbox{ where }a,\, b\, >\, 0,\, \mbox{ is....}[/tex]
Starting fresh: The only way to have "more than one solution" is to have infinitely-many solutions. In such a situation, the equations are the same, other than some multiple; in particular, one can make them the same via clever multiplications.
So multiply each of the rows in order to make at least one of the terms (say, the first one in each) identical. Then you know that the other terms must be equal. Set them equal, and solve for the values of a and b. Pick the pair of values that are positive, and add.
I do get one of the listed answers.
i dont even know if what im doing right now is even close to it beign right...
what.jpg
could someone please show me how to work this out, a solution to this answer maybe. Also what should i be looking at to understand this question if my attempt is not even close. :\
I would rewrite those equations as:1. The following system of equations has more than
one solution (x,y).
. . . .2ax+6y=5
. . . .4x+3ay=b
The value of a+b where a,b>0, is....
[tex]\displaystyle \frac{2a}{5}x \ + \ \frac{6}{5}y \ = \ 1[/tex]
and
[tex]\displaystyle \frac{4}{b}x \ + \ \frac{3a}{b}y \ = \ 1[/tex]
Now equate the coefficients of 'x' of the two equations.
do similarly for the coefficients of 'y'.
Now solve....
“... mathematics is only the art of saying the same thing in different words” - B. Russell
sorry i dont understand any of this now :\, could you just please tell me what the answer is? on my first attempt at the very top ^, i managed to get 5 (B)... is this correct? if not which is the answer?
“... mathematics is only the art of saying the same thing in different words” - B. Russell
Try following the specific step-by-step instructions I'd provided you earlier. In particular, instead of creating some sort of system of equations after the cancellation (due to one pair of terms obviously being equal), try doing what I said (and which I'd advised does lead to the correct answer): Set the other pairs of terms equal, too. Solve.
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