Similar Right triangles, find altitude

[HCL]

I hope you can see that but it says that all triangles are similar then asks for the altitude given 2 hypos. 2 hypos/side are 20 and 15 respectively. Can't figure this out, found the side JL = 25 but still can't figure out how to calculate the altitude/KM

 

[serds]

The triangles are similar, because 3 pairs of correspondending sides are in the same ratio.
So here we have: 25:20:15 = 5:4:3.
Now you have to find: 20:JM:KM.

 

[pka]

View attachment 3122
found the side JL = 25 but still can't figure out how to calculate the altitude/KM

Note that the area of \(\displaystyle \Delta KJL\) is \(\displaystyle 150\).

Use the area formula.

But \(\displaystyle \overline{KM}\) is an altitude to base \(\displaystyle \overline{JL}\)