\(\displaystyle \int_{1}^{5} 3^{2x} dx\)
Using \(\displaystyle \int a^{u} du = \dfrac{a^{u}}{\ln a} + C\) and \(\displaystyle \dfrac{d}{dx} (a^{u}) = a^{u} * du * \ln a\)
\(\displaystyle u = 3^{2x}\)
\(\displaystyle du = 3^{2x} * 2 dx * \ln 3\)
Hint on next step? Do I put something to the left of the intergal sign at some point?
Using \(\displaystyle \int a^{u} du = \dfrac{a^{u}}{\ln a} + C\) and \(\displaystyle \dfrac{d}{dx} (a^{u}) = a^{u} * du * \ln a\)
\(\displaystyle u = 3^{2x}\)
\(\displaystyle du = 3^{2x} * 2 dx * \ln 3\)
Hint on next step? Do I put something to the left of the intergal sign at some point?
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