The sum of three consecutive odd integers is -87. What are the integers?
The sum of three consecutive odd integers is -87. What are the integers?
You have posted 4 problems, and showed no work whatsoever.
Did you read "Read before posting"?
Is you teacher aware that you're trying to get your homework done?
I'm just an imagination of your figment !
I'm sorry that I'm asking for what seems like a lot of help (but you don't know how much homework I have and I'm in Algebra) and that it seems like I'm asking for other people to do my work for me but:
1. I'm not asking other people to do it for me, sorry if I wasn't clear that I just wanted an explanation on a lesson that I was sick for and that I couldn't get the lesson from my teacher when I got back. Also, I was just asking for an explanation on how to do it.
2. I just need some help. Which when I saw that I had a reply to a question I submitted, I was relieved to be getting help which I didn't and that wasn't helping me in my state right now in the least bit.
I'm sorry that I wasn't clear on that.
The sum of three consecutive odd integers is -87. What are the integers?
2n+1 is odd
(2n+3)(2n+5) are 2 consecutive odd integers
"What happens in the event horizon, stays in the event horizon" -- Bob Brown (grandpa Bob)
OK, let's take your word for it!
Your question is:
"The sum of three consecutive odd integers is -87. What are the integers?"
An odd integer is usually represented by 2n+1.
So 3 consecutive ones can be: 2n+1, 2n+3, 2n+5
SO: 2n+1+2n+3+2n+5 = -87
That's the "equation"; solve it for n.
I'm just an imagination of your figment !
It probably would have been helpful to have mentioned that, right at the beginning. Since what you're wanting is a lesson on this kind of word problem, here's a list: Google results for "number word problems.
There's no need for those descriptions. Consecutive odd integers (and consecutive even integers as well) differ by two.
It is sufficient to let the three consecutive odd integers be: n, n + 2, n + 4.
So: Solve the following equation for n and substitute that value into the 2nd and 3rd expressions to get the other two numbers:
[tex]n \ \ + \ \ n + 2 \ \ + \ \ n + 4 \ = \ -87[/tex]
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