Algebra 1

Sorry that it seems that way.

You have posted 4 problems, and showed no work whatsoever.

Did you read "Read before posting"?

Is you teacher aware that you're trying to get your homework done?

I'm sorry that I'm asking for what seems like a lot of help (but you don't know how much homework I have and I'm in Algebra) and that it seems like I'm asking for other people to do my work for me but:
1. I'm not asking other people to do it for me, sorry if I wasn't clear that I just wanted an explanation on a lesson that I was sick for and that I couldn't get the lesson from my teacher when I got back. Also, I was just asking for an explanation on how to do it.
2. I just need some help. Which when I saw that I had a reply to a question I submitted, I was relieved to be getting help which I didn't and that wasn't helping me in my state right now in the least bit.

I'm sorry that I wasn't clear on that.
 
The sum of three consecutive odd integers is -87. What are the integers?

2n+1 is odd
(2n+3)(2n+5) are 2 consecutive odd integers

 
OK, let's take your word for it!
Your question is:
"The sum of three consecutive odd integers is -87. What are the integers?"

An odd integer is usually represented by 2n+1.
So 3 consecutive ones can be: 2n+1, 2n+3, 2n+5

SO: 2n+1+2n+3+2n+5 = -87
That's the "equation"; solve it for n.

There's no need for those descriptions. Consecutive odd integers (and consecutive even integers as well) differ by two.

It is sufficient to let the three consecutive odd integers be: n, n + 2, n + 4.


So: Solve the following equation for n and substitute that value into the 2nd and 3rd expressions to get the other two numbers:



\(\displaystyle n \ \ + \ \ n + 2 \ \ + \ \ n + 4 \ = \ -87\)
 
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