I am familiar with completing the square of a binomial.
I take the equation ax^2 + bx + c = 0
Subtract c from both sides and divide both sides by a
I then add b^2/(4*a^2) to both sides
Take the square root and I get the quadratic equation.
I want to derive a cubic equation for:
ax^3 + bx^2 + cx + d = 0
I subtracted d from both sides
divided both sides by a
Then I added (b^3*c^3)/(27*a^3)
This did not yield the solution of
(x + something)^3 = something
so I couldn't take the cube root and solve.
Any ideas?
I take the equation ax^2 + bx + c = 0
Subtract c from both sides and divide both sides by a
I then add b^2/(4*a^2) to both sides
Take the square root and I get the quadratic equation.
I want to derive a cubic equation for:
ax^3 + bx^2 + cx + d = 0
I subtracted d from both sides
divided both sides by a
Then I added (b^3*c^3)/(27*a^3)
This did not yield the solution of
(x + something)^3 = something
so I couldn't take the cube root and solve.
Any ideas?