Trig identities

Csanchez

New member
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Nov 6, 2013
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Would
Cos(θ-π)sin(θ+π)
Simplify to 1/2[sin2θ+sin2π]
Or would you have to continue to simplify sin 2π to 0 and end up with 1/2[sin2θ]
Sinθ?
 
In general, any numerical value should be evaluated and simplified as much as possible. So "sin(2(pi))" should definitely be converted to "0". ;)
 
Would
Cos(θ-π)sin(θ+π)
Simplify to 1/2[sin2θ+sin2π]
Or would you have to continue to simplify sin 2π to 0 and end up with 1/2[sin2θ]
Sinθ? ..............where did that come from?

Alternate answer could be:

Cos(θ-π)sin(θ+π) = [-cos(Θ)] * [-sin(Θ)] = cos(Θ) * sin(Θ)
 
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