Hi there. Just got back a math test and wanted someone explain my wrong answers to me, if any of you would.
1) tan(42/6) = 0, pi ...I got marked down for the pi
2) arcsin(1/2) = pi/6, 5pi/6 ...I got marked down for the 5pi/6
3)csc[arcsin(1/2) = pi/6, 5pi/6 ...I got marked down for the 5pi/6
4) tan(x) + 2cos(x) = sec(x)
I solved this for (2sin -1)(sin-1) so sin = -1/2, 1 = pi/2, 11pi/2, 7pi/2 ...i got marked down for the pi/2
5) Establish identity:
sec(x) - tan(x) = cos(x)/(1+sin(x))
1/cos - sin/cos + sin/cos - sin^2/cos
(1-sin^2)/cos = cos
1-sin^2 = cos^2
(i got no credit for this)
Did I just make a ton of little mistakes?
thank you. and, obviously, I'm open to reworking any problem that you want me to.
1) tan(42/6) = 0, pi ...I got marked down for the pi
2) arcsin(1/2) = pi/6, 5pi/6 ...I got marked down for the 5pi/6
3)csc[arcsin(1/2) = pi/6, 5pi/6 ...I got marked down for the 5pi/6
4) tan(x) + 2cos(x) = sec(x)
I solved this for (2sin -1)(sin-1) so sin = -1/2, 1 = pi/2, 11pi/2, 7pi/2 ...i got marked down for the pi/2
5) Establish identity:
sec(x) - tan(x) = cos(x)/(1+sin(x))
1/cos - sin/cos + sin/cos - sin^2/cos
(1-sin^2)/cos = cos
1-sin^2 = cos^2
(i got no credit for this)
Did I just make a ton of little mistakes?
thank you. and, obviously, I'm open to reworking any problem that you want me to.