Inverse trig problem
- Thread starter Ahenry20
- Start date
- Joined
- Feb 4, 2004
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Where are you stuck?
You've drawn a right triangle (not "to scale" or anything; it's just to hold the values and variables); you've labelled the base angle as, say, "theta" (I'll use "@" here); noted that "cos^(-1)(x/3) = @" means "cos(@) = x/3"; labelled the "adjacent" and "hypotenuse" accordingly; applied the double-angle formula to tan(2@); and... then what?
Please be complete. Thank you! ;-)