Parallel_Platypus
New member
- Joined
- Dec 9, 2013
- Messages
- 8
rectangle and right angled triangle with equal area and a combined perimeter of 44
I believe I could solve the problem through trial and error, but I am curious of the algebraic method of solving the problem. I though a set of simultaneous equations would have worked, but I can't derive enough equations to solve it. This is my only working, as such:
The rectangle has sides a and b. Triangle has sides c, d, and e (where e is equal to the square root of c^2 + d^2)
Therefore- ab=1/2cd
And 2a+2b+c+d+ ((square root of c^2 + d^2) or e)=44
Am I approaching the problem incorrectly, or do I need to correct my notation and derive more equations?
Thx in advance
I believe I could solve the problem through trial and error, but I am curious of the algebraic method of solving the problem. I though a set of simultaneous equations would have worked, but I can't derive enough equations to solve it. This is my only working, as such:
The rectangle has sides a and b. Triangle has sides c, d, and e (where e is equal to the square root of c^2 + d^2)
Therefore- ab=1/2cd
And 2a+2b+c+d+ ((square root of c^2 + d^2) or e)=44
Am I approaching the problem incorrectly, or do I need to correct my notation and derive more equations?
Thx in advance
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